Answered

This is a literal equation.

Solve for A.

2 2
V = V_0 + 2aΔx




( The second 'V' variable is squared and subscripted with a zero)



Answer :

mashenka
Assuming this is the equation you want to operate on:
[tex] v^{2} = (v_0)^{2} + 2\cdot a \cdot \Deltax [/tex]
[tex] 2\cdot a \cdot \Delta x = v^{2} - (v_0)^{2} [/tex]
[tex] a = \frac{v^{2} - (v_0)^{2}}{2\cdot \Delta x} [/tex]
Before final operation we have to assume that x is not equal to 0. :)
konrad509
[tex]V^2=V_0^2+2a\Delta x\\ 2a\Delta x=V^2-V_0^2\\ a=\frac{V^2-V_0^2}{2\Delta x} [/tex]

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