Answer :
[tex]x-length\ of\ one\ side\ of\ base\\y-high\ of\ box\\x^2-area\ of\ base\\x^2y-volume\\\\x^2y=70\\y=\frac{70}{x^2}\ \ \ \ \ \ \ \ and\ x\neq0\\\\38x^2+4\cdot10xy+27x^2\\65x^2+40xy\ in\ cents\\\\0.65x^2+0.4xy\ in\ dollars[/tex]