Answer :
[tex]\angle \ A+ \angle \ B=90^0 \\ \\ \angle \ B+ \angle \ C=180^0 \\\\ \angle \ B+127^0=180^0 \\ \\ \angle \ B=180^0-127^0 \\ \\ \boxed{ \angle \ B=53^0} \\ \\ \\ \angle \ A=90^0-53^0 \\ \\ \boxed{ \angle \ A=37^0}[/tex]