Answer :

[tex]\frac{5t-3}{-2}=\frac{t+3}{2} \\\\ 2(5t-3)=-2(t+3) \\\\ 10t-6=-2t-6 \\\\ 10t+2t=-6+6\\\\ 12t=0 \\\\ \boxed{t=0}[/tex]

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