Answer :
2/(2+ square root of 3)you need to multiply by whats called the conjugate
2/(2+ square root of 3) x 2-√3[tex] \frac{2}{2+ \sqrt{3} } * \frac{2- \sqrt{3} }{2- \sqrt{3} } = 4-2 \sqrt{3} [/tex}
2/(2+ square root of 3) x 2-√3[tex] \frac{2}{2+ \sqrt{3} } * \frac{2- \sqrt{3} }{2- \sqrt{3} } = 4-2 \sqrt{3} [/tex}
