Answer :
[tex]\frac12 in -\frac38 ft \\
8\frac48 in - x\ ft\\
\\
\frac12x=\frac38 \cdot 8\frac49\\
\frac12x=\frac38 \cdot \frac{76}9\\
\frac12x=\frac{76}{24}\ /\cdot 2\\
x=\frac{76}{12}=6\frac13 ft\\\\
Answer:Actual\ lenght\ is\ 6\frac13ft.[/tex]