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A railway engine I mass 6000kg travelling at 4m/s collided with and coupled to a truck of mass 2000kg that was in totally not moving
A.) calculate the momentum before the collision of the engine

B.) show that the engine and the truck moved at a velocity of 3m/s after the collision



Answer :

A) Momentum (p) = Mass (m) × Velocity (v)

Initial momentum (p₀) = (6000 kg)(4 m/s) + (2000 kg)(0 m/s) = 24000 kg·m/s

B)  Conservation of Momentum states that the initial momentum must equal the final momentum.  Find velocity (v) after collision . . .

(6000 kg)(4 m/s) + (2000 kg)(0 m/s) = (6000 kg)(v m/s) + (2000 kg)(v m/s)

(6000)(4) + (2000)(0) = (6000)v + (2000)v

(24000) + (0) =(6000 + 2000)v

24000 = 8000v

24000/8000 = v

24/8 = v

3 = v

Thus:

v = 3 m/s
The answer is A calculate the monumentum before the collision of the engine.

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