Answer :
Wow, now this one is a hard one, took me quite a while to figure it out but here it is:
[tex]120.904(x)+122.904(1-x)=121.76 \\ 120.904x-122.904x+122.904=121.76 \\ -2x+122.904=121.76 \\ -2x=-1.144 \\ x=.572 \\ 1-.572=.428[/tex]
The abundances of the two isotopes is:
Antimony-121 = 57.2%
Antimony-123 = 42.8%
[tex]120.904(x)+122.904(1-x)=121.76 \\ 120.904x-122.904x+122.904=121.76 \\ -2x+122.904=121.76 \\ -2x=-1.144 \\ x=.572 \\ 1-.572=.428[/tex]
The abundances of the two isotopes is:
Antimony-121 = 57.2%
Antimony-123 = 42.8%