Answer :
[tex]a,a+1,a+2-\ three\ consecutve\ integers\\\\
3*(a+2)+2=5*(a+3)+3(a+1)\\\\
3a+6+2=5a+15+3a+3\\\\
3a+8=8a+18\ \ \ | subtract\ 3a\\\\
8=5a+18\ \ \ \ | subtract\ 18\\\\
-10=5a\ \ \ \ | divide\ by\ 5\\\\
a=-2\\\\Numbers\ are:\ \ -2,-1,0
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