Answer :
price paid:
moores = cotters + 6
moores + cotters + 6 = 30
therefore:
moores + cotters = 24
[substitute moores = cotters + 6 into moores + cotters = 24]
cotters + 6 + cotters = 24
2 cotters = 18
cotters = 9
[substitute cotters = 9 into moores = cotters + 6]
moores = 9 + 6 = 15
you haven't said of the families have membership, but on skate rentals alone:
15 / 3 = 5 pairs of skates
moores = cotters + 6
moores + cotters + 6 = 30
therefore:
moores + cotters = 24
[substitute moores = cotters + 6 into moores + cotters = 24]
cotters + 6 + cotters = 24
2 cotters = 18
cotters = 9
[substitute cotters = 9 into moores = cotters + 6]
moores = 9 + 6 = 15
you haven't said of the families have membership, but on skate rentals alone:
15 / 3 = 5 pairs of skates
Answer:
The Moore spent 3(18)=$54.
The Cotters spent 3(12)=$36.
Step-by-step explanation:
The problem doesn't specifies which family has membership card, and which one doesn't.
According to the problem, The Moore's paid $6.00 more than the Cotter's. Both families paid $30. So, with this relations we can solve the problem.
The difference between families is represented by:
[tex]M=C+6[/tex]
And the total amount of money is:
[tex]M+C=30[/tex]
Replacing the first equation in the second one:
[tex]C+6+C=30[/tex]
[tex]2C=30-6\\C=\frac{24}{2}=12[/tex]
Replacing this value in the second equation, we have:
[tex]M+12=30[/tex]
[tex]M=30-12=18[/tex]
According to these results, the Moore's rented 18 pair of skates, and the Cotter's 12 pairs.
If Skate rental are $3.00, then:
The Moore spent 3(18)=$54.
The Cotters spent 3(12)=$36.
