Answer :
The equation represents a circle.
If you factorise the equation, you get:
[tex]x^2 + y^2 + 2x +1 =0 \\(x+1)^2-1+(y)^2=0\\(x+1)^2+y^2=1[/tex]
This final equation shows the equation of a circle, as a circle's equation is given as:
[tex](x+a)^2+(y+b)^2=r^2[/tex]
If you factorise the equation, you get:
[tex]x^2 + y^2 + 2x +1 =0 \\(x+1)^2-1+(y)^2=0\\(x+1)^2+y^2=1[/tex]
This final equation shows the equation of a circle, as a circle's equation is given as:
[tex](x+a)^2+(y+b)^2=r^2[/tex]
It a circle because, the equation is a degree 2 equation. That is squared.
The coefficient of x^2 and y^2 are the same.
There is no term term xy.
And a parabola is of the form y^2 = 4ax or x^2 = 4ay.
And an ellipse is of the form: (x^2)/(a^2) + (y^2)/(b^2) = 1.
The coefficient of x^2 and y^2 are the same.
There is no term term xy.
And a parabola is of the form y^2 = 4ax or x^2 = 4ay.
And an ellipse is of the form: (x^2)/(a^2) + (y^2)/(b^2) = 1.
