Answer :
Let n be the original number
[tex]2n - 3 \\ \frac{16n}{2} \\ 3(n^{2}) [/tex]
[tex] \frac{n^{2}}{2} - 6 \\ 8- \frac{n}{2} \\ 23-\frac{n^{3}}{2} [/tex]
[tex]2n - 3 \\ \frac{16n}{2} \\ 3(n^{2}) [/tex]
[tex] \frac{n^{2}}{2} - 6 \\ 8- \frac{n}{2} \\ 23-\frac{n^{3}}{2} [/tex]