Answer :
[tex]3\frac{1}{5}-1\frac{3}{10}=p+\frac{5}{6}\\\\3\frac{2}{10}-1\frac{3}{10}-\frac{5}{6}=p\\\\p=2\frac{12}{10}-1\frac{3}{10}-\frac{5}{6}\\\\p=1\frac{9}{10}-\frac{5}{6}\\\\p=1\frac{27}{30}-\frac{25}{30}\\\\p=1\frac{2}{30}\\\\p=1\frac{1}{15}[/tex]
