Answer :
9 g of hydrogen - 42 g of nitrogen
5 g of hydrogen - x g of nitrogen
[tex]9x=42 \cdot 5 \\ 9x=210 \\ x \approx 23.33[/tex]
The mass of nitrogen in the second sample is 23.33 g.
5 g of hydrogen - x g of nitrogen
[tex]9x=42 \cdot 5 \\ 9x=210 \\ x \approx 23.33[/tex]
The mass of nitrogen in the second sample is 23.33 g.