Answer :
Ek = 1/2 × m × v² ;
Ek...kinetic energy
m...mass
v...velocity
If we double the velocity,then Ek = 1/2 × m × (2×v)² = 1/2 × m × 4×v² = 2×m×v²
[tex] \frac{2*m*v ^{2} }{ \frac{1}{2}*m*v^2 } = 4[/tex] so the correct answer is C
Ek...kinetic energy
m...mass
v...velocity
If we double the velocity,then Ek = 1/2 × m × (2×v)² = 1/2 × m × 4×v² = 2×m×v²
[tex] \frac{2*m*v ^{2} }{ \frac{1}{2}*m*v^2 } = 4[/tex] so the correct answer is C
