Answer :

[tex]f(x)=\log_4x\\\\ y=\log_4x\\ x=4^y\\ f^{-1}(x)=4^x[/tex]
[tex]f\left( x \right) =\log _{ 4 }{ x } \\ \\ \log _{ 4 }{ x } =y\\ \\ { 4 }^{ y }=x\\ \\ \therefore \quad { f }^{ -1 }\left( x \right) ={ 4 }^{ x }[/tex]

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