Answer :

luana
[tex]-\frac{1}{6}+\frac{2}{3}(9-\frac{3}{4})-\frac{1}{2}=\ \ \ \ \ | make\ common\ denominator\\\\ -\frac{2}{12}+\frac{8}{12}(9-\frac{9}{12})-\frac{6}{12}=\\\\ -\frac{2}{12}+\frac{72}{12}-\frac{72}{144}-\frac{6}{12}=\\\\ -\frac{2}{12}+\frac{72}{12}-\frac{6}{12}-\frac{6}{12}=\\\\ \frac{-2+72-6-6}{12}=\frac{58}{12}\\\\ Solution\ is\ \frac{58}{12}. [/tex]

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