Answer :
[tex] \frac{9}{10} - \frac{1}{3} \\ \frac{9(3)}{10(3)}- \frac{1(10)}{3(10)} \\ \frac{27}{30}- \frac{10}{30} \\ \frac{17}{30} [/tex]
First find the GCF of 10 and 3 --> 30
[tex] \frac{9}{10} [/tex] x [tex] \frac{3}{3} [/tex] = [tex] \frac{27}{30} [/tex]
[tex] \frac{1}{3} [/tex] x [tex] \frac{10}{10} [/tex] = [tex] \frac{10}{30} [/tex]
Now subract [tex] \frac{27}{30} - \frac{10}{30} [/tex]
Answer = [tex] \frac{17}{30} [/tex]
Reduce if possible -- cant reduce further..
answer 17/30
[tex] \frac{9}{10} [/tex] x [tex] \frac{3}{3} [/tex] = [tex] \frac{27}{30} [/tex]
[tex] \frac{1}{3} [/tex] x [tex] \frac{10}{10} [/tex] = [tex] \frac{10}{30} [/tex]
Now subract [tex] \frac{27}{30} - \frac{10}{30} [/tex]
Answer = [tex] \frac{17}{30} [/tex]
Reduce if possible -- cant reduce further..
answer 17/30
