Answer :
the two longer sides of a right angle triangle are 16 and 22
let 22 be the hypotenuse (the longest side)
use Pythagoras Therom a²+b²=c²
in this question c=22 and b=16
to find the shortest side
22²-16²=a²
484-256=a²
228=a²
a=√(228)
a= 15.1
let 22 be the hypotenuse (the longest side)
use Pythagoras Therom a²+b²=c²
in this question c=22 and b=16
to find the shortest side
22²-16²=a²
484-256=a²
228=a²
a=√(228)
a= 15.1
The formula a2xb2=c2 will help with this problem.
The longest sides, so the longer one is c2. the next is either a2 or b2. 2, in this case, is an exponent, so we multiply the number by itself.
So, a2+(16x16)=(22x22)
16 times 16 is 256. 22 times 22 is 484.
a2+256=484. 484-256 will leave you a2. Then, 484-256=228. Since a2 is still squared, you need to find the square root of 228. (which is about 15.1)
So of your answer choices, if it is among them, choose 15.
Hope I helped!!!!
