Answer :
so first solve for x and y
add the 2 equations together
2x+x+y-y=-8-4
3x=-12
divide by 3
x=-4
subsitute
-4-y=-4
addd 4 to both sdies
-y=0
the solution is (x,y) (-4,0) or D
add the 2 equations together
2x+x+y-y=-8-4
3x=-12
divide by 3
x=-4
subsitute
-4-y=-4
addd 4 to both sdies
-y=0
the solution is (x,y) (-4,0) or D
So,
I have decided to use Elimination by Addition.
Add the two equations together
3x = -12
Divide both sides by 3
x = -4
Substitute -4 for x in the second equation.
-4 - y = -4
Add 4 to both sides
-y = 0
y = 0
Check
2(-4) + 0 = -8
-8 = -8 This checks.
-4 - 0 = -4
-4 = -4 This also checks.
The solution set for this system is as follows:
S = {(-4,0)}
That would be option D.
I have decided to use Elimination by Addition.
Add the two equations together
3x = -12
Divide both sides by 3
x = -4
Substitute -4 for x in the second equation.
-4 - y = -4
Add 4 to both sides
-y = 0
y = 0
Check
2(-4) + 0 = -8
-8 = -8 This checks.
-4 - 0 = -4
-4 = -4 This also checks.
The solution set for this system is as follows:
S = {(-4,0)}
That would be option D.
