Answer :
Each term is 10 times smaller than the previous one.
[tex]0.3x+0.03x+0.003x+0.0003x+\ldots=3\\ x(0.3+0.03+0.003+0.0003+\ldots)=3\\ x\cdot0.\overline{3}=3\\ x\cdot\dfrac{1}{3}=3\\ x=9[/tex]
[tex]0.3x+0.03x+0.003x+0.0003x+\ldots=3\\ x(0.3+0.03+0.003+0.0003+\ldots)=3\\ x\cdot0.\overline{3}=3\\ x\cdot\dfrac{1}{3}=3\\ x=9[/tex]
