Answer :
[tex]\frac{6}{5}x+ \frac{8}{45}= \frac{2}{3}x \\\\\frac{6}{5}x- \frac{2}{3}x =-\frac{8}{45} \\\\\frac{18}{15}x- \frac{10}{15}x =-\frac{8}{45} \\\\\frac{8}{15}x =-\frac{8}{45}\ \ / *\frac{15}{8}\\\\x=-\frac{1}{3}[/tex]
