Answer :

[tex]5(4c-2d)+2d-6(d-3c)\ |\ distribute\ 5\ to\ 4c\ and\ -2d \\ 20c-10d+2d-6(d-3c)\ |\ distribute\ -6\ to\ d\ and\ -3c \\ 20c-10d+2d-6d+18c\ |\ group\ like\ terms \\ 20c-18c-10d+2d-6d \\ (20-18)c + (-10+2-6)d \\ \boxed{2c -14d}[/tex]
5(4c-2d) +2d-6(d-3c)
(5x4c) + (5x-2d) +2d-6(d-3c)
20c+-10d            (6*1d) + (6*-3c)
                         6d + -18c + 2d
group like terms 
( 20c +-18c)+ (-10d+6d+2d)
2c+ -2d

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