Answer :
Use the formula for the area of a rectangle to find the width.
[tex]A = wl\ \ \ \ \ (plug\ in\ values) \\ 11\frac{7}{8} = 4\frac{3}{4}l\ (put\ into\ improper\ fractions)\\ \frac{95}{8}=\frac{38}{8}l\ \ \ (multiply\ by\ 8) \\ 95=38l\ \ \ (divide\ by\ 19)\\ 5 = 2l\ \ \ \ \ \ (divide\ by\ 2)\\ \frac{5}{2}=l\ \ \ \ \ \ \ (put\ as\ mixed\ number) \\\\ \boxed{l=2\frac{1}{2}\ ft}[/tex]
[tex]A = wl\ \ \ \ \ (plug\ in\ values) \\ 11\frac{7}{8} = 4\frac{3}{4}l\ (put\ into\ improper\ fractions)\\ \frac{95}{8}=\frac{38}{8}l\ \ \ (multiply\ by\ 8) \\ 95=38l\ \ \ (divide\ by\ 19)\\ 5 = 2l\ \ \ \ \ \ (divide\ by\ 2)\\ \frac{5}{2}=l\ \ \ \ \ \ \ (put\ as\ mixed\ number) \\\\ \boxed{l=2\frac{1}{2}\ ft}[/tex]
