Answer :

[tex](2+3i)(4-i)=\\ 8-2i+12i+3=\\ 11+10i[/tex]
(2 + 3i)(4 - i)
8 - 2i + 12i - 3i²
8 + 10i - 3(-1)
8 + 10i + 3
8 + 3 + 10i
11 + 10i

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