Before we solve this equation, we need to simplify it. x²-25 will simplify to (x-5)(x+5). x²-2x would simplify to x(x-2) after we factor out a x. x-2 is prime, so we won't do anything to it. x²+5x will simplify to x(x+5) after we factor out an x.
Now this is what we have:
[tex][(x-5)(x+5) ]/x(x-2) * (x-2)/[x(x+5)][/tex]
If we look at the top and the bottom of the fractions, we see that we have two x-2's and two x+5. Those will cancel out.
[tex][(x-5)/x]*(1/x)[/tex]
Now we will multiply across to get
[tex](x-5)/x^2[/tex]