Answer :
y = x² - 6x + 5
0 = x² - 6x + 5
x = -(-6) +/- √((-6)² - 4(1)(5))
2(1)
x = 6 +/- √(36 - 20)
2
x = 6 +/- √(16)
2
x = 6 +/- 4
2
x = 3 + 2
x = 3 + 2 x = 3 - 2
x = 5 x = 1
y = x² - 6x + 5
y = (5)² - 6(5) + 5
y = 25 - 30 + 5
y = -5 + 5
y = 0
(x, y) = (5, 0)
or
y = x² - 6x + 5
y = (1)² - 6(1) + 5
y = 1 - 6 + 5
y = -5 + 5
y = 0
(x, y) = (1, 0)
The x-intercept of the problem is equal to 5 or 1.
0 = x² - 6x + 5
x = -(-6) +/- √((-6)² - 4(1)(5))
2(1)
x = 6 +/- √(36 - 20)
2
x = 6 +/- √(16)
2
x = 6 +/- 4
2
x = 3 + 2
x = 3 + 2 x = 3 - 2
x = 5 x = 1
y = x² - 6x + 5
y = (5)² - 6(5) + 5
y = 25 - 30 + 5
y = -5 + 5
y = 0
(x, y) = (5, 0)
or
y = x² - 6x + 5
y = (1)² - 6(1) + 5
y = 1 - 6 + 5
y = -5 + 5
y = 0
(x, y) = (1, 0)
The x-intercept of the problem is equal to 5 or 1.
