Answer :

[tex]\frac{4x-8}{x^2-2x}=\frac{4(x-2)}{x(x-2)}=\frac{4}{x}\\\\\\\\x^2-2x\neq0\Rightarrow x(x-2)\neq0\Rightarrow x\neq0\ \wedge\ x\neq2[/tex]

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