Answer :
Formula: q=m*c*(change in T)
q= 418.6
m=26.86
c= X(unknown)
(Change in T)= (67.3-27.4 = 39.9)
Now you solve for X, I got .391.
So the specific heat of this certain metal is .391 j/gram C
q= 418.6
m=26.86
c= X(unknown)
(Change in T)= (67.3-27.4 = 39.9)
Now you solve for X, I got .391.
So the specific heat of this certain metal is .391 j/gram C