The playing board of a new game has a perimeter of 78 inches. It was designed so that the length is 6 inches shorter than double the width. What are the dimensions of the playing board?



Answer :

Answer:

Length 24; Width: 15

Step-by-step explanation:

Lets set up a system of equations to solve:

The perimeter is 78 so :

2l + 2w = 78    ;  l = length and w = width

The length is 6 shorter than twice the width so:

l = 2w - 6

We can plug in l = 2w - 6 for l in the first equation:

2(2w - 6) + 2w = 78

4w - 12 + 2w = 78

6w = 90

w = 15

Now we can plug the width back into the second equation to solve for l

l = 2w - 6

l = 2(15) - 6

l = 24

Length 24; Width: 15

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