Answer:
The function ( f(x) ) is not differentiable at ( x = 3 ) because it is not continuous at that point. This is also the point where the function has a removable discontinuity. Everywhere else, the function is differentiable.
Step-by-step explanation:
( f(x) = \frac{x^2 - 9}{x - 3} )
This simplifies to:
( f(x) = \frac{(x - 3)(x + 3)}{x - 3} )
When ( x \n 3 ), the ( x - 3 ) terms cancel out, leaving:
( f(x) = x + 3 )
