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An individual is performing squat reps. The bar plus weights weighs 667 N. The bar is lifted a total of 1.23 m from the bottom of the squat to full extension. How much work was done on the weight?



Answer :

regalmocha17

Answer:

820.41 J

Explanation:

Equation to Use:

W = Fd

W = work

f = force

d = distance/displacement

Known Values:

f = 667 N

d = 1.23 m

Input and Solve:

W = 667(1.23)

W = 820.41 J

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