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Finish the two parts of the piecewise function:

Rosa saved $100 to spend on vacation. For the first 3 days of her vacation she spent $20 each day. Then for the next 2 days, she spent nothing. After those 5 days, she spent $10 each day until her savings were depleted.

View photo, I've done a lot of the work, just can't figure out the 1st and 3rd equations.

Finish the two parts of the piecewise function Rosa saved 100 to spend on vacation For the first 3 days of her vacation she spent 20 each day Then for the next class=


Answer :

Answer:

[tex]f(x) = \begin{cases} 100 - 20x\quad 0 \leq x \leq 3 \\40\qquad \qquad\: 3 < x \leq 5 \\90 - 10x \quad \:\:5 < x\leq9\end{cases}[/tex]

Step-by-step explanation:

Day 0 to Day 3

Rosa begins her vacation with $100 in savings. Over the first three days, she spends $20 each day. Therefore, her savings decrease by $20 per day. If we let [tex]x[/tex] represent the number of days since the start of her vacation, her savings after [tex]x[/tex] days can be calculated by subtracting $20 multiplied by [tex]x[/tex] from her initial $100. This gives us the function:

[tex]f(x) = 100 - 20x[/tex]

This applies for the days from 0 to 3 inclusive, so the interval is:

[tex]0 \leq x \leq 3[/tex]

[tex]\dotfill[/tex]

Day 4 to Day 5

On the fourth and fifth days of her vacation, Rosa does not spend any money.

As she spends $20 each day for the first 3 days, by the end of the third day, she has already spent $20 × 3 = $60, leaving her with:

[tex]\$100 - \$60 = \$40[/tex]

Since there is no spending on the fourth and fifth days, her savings remain constant at $40 during this period. Hence, the function representing her savings on these days is:

[tex]f(x) = 40[/tex]

This is valid for the interval:

[tex]3 < x \leq 5[/tex]

[tex]\dotfill[/tex]

Day 6 onwards

Starting from the sixth day, Rosa resumes spending, but now at a reduced rate of $10 per day.

At the beginning of the sixth day, she has $40. For each additional day beyond the fifth, she spends $10, reducing her savings by $10 each day.

To express the number of days since the end of the fifth day, we use [tex]x-5[/tex]. Therefore, her savings after [tex]x[/tex] days can be calculated by subtracting $10 multiplied by [tex]x-5[/tex] from $40:

[tex]f(x) = 40 - 10(x - 5)[/tex]

Simplify:

[tex]f(x) = 40 - 10x + 50 \\\\ f(x) = 90 - 10x[/tex]

This function applies for the interval:

[tex]5 < x\leq9[/tex]

[tex]\dotfill[/tex]

Complete Piecewise Function

Therefore, the complete piecewise function that describes Rosa's savings over the duration of her vacation is:

[tex]f(x) = \begin{cases} 100 - 20x\quad 0 \leq x \leq 3 \\40\qquad \qquad\: 3 < x \leq 5 \\90 - 10x \quad \:\:5 < x\leq9\end{cases}[/tex]

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