A person weighing 700 N is standing on one foot with an area of 0.02 m²
What is the pressure exerted on the ground?



Answer :

To find the pressure exerted on the ground, we can use the formula:

[tex]\[ \text{Pressure} = \frac{\text{Force}}{\text{Area}} \][/tex]

Here, the force is the weight of the person, and the area is the surface area of the foot in contact with the ground.

Given:
- The weight (force) of the person [tex]\( F = 700 \)[/tex] Newtons (N)
- The area of one foot [tex]\( A = 0.02 \)[/tex] square meters (m²)

We can substitute these values into the formula:

[tex]\[ \text{Pressure} = \frac{700 \, \text{N}}{0.02 \, \text{m}^2} \][/tex]

Perform the division:

[tex]\[ \text{Pressure} = \frac{700}{0.02} \][/tex]

[tex]\[ \text{Pressure} = 700 \div 0.02 \][/tex]

[tex]\[ \text{Pressure} = 35,000 \][/tex]

Therefore, the pressure exerted on the ground is:

[tex]\[ \text{Pressure} = 35,000 \, \text{Pascals (Pa)} \][/tex]

This means the person standing on one foot, with the given area, exerts a pressure of 35,000 Pascals on the ground.

Other Questions