Answer :

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To determine the number of moles of sodium hydroxide (NaOH) needed to neutralize 25 mL of 0.1 M hydrochloric acid (HCl), follow these steps:

1. Calculate the moles of HCl.

  - Molarity of HCl = 0.1 M

  - Volume of HCl = 25 mL = 0.025 L

  Moles of HCl = Molarity * Volume

  Moles of HCl = 0.1 * 0.025

  Moles of HCl = 0.0025 moles

2. Since the reaction between NaOH and HCl is 1:1, the moles of NaOH needed will be equal to the moles of HCl.

  Moles of NaOH needed = 0.0025 moles

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