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A gas that exerts a pressure of 151 mm Hg in a container with an unknown volume will exert a pressure of 166 mm Hg when transferred to a 0.532 L container.

What is the initial volume [tex]\(V_1\)[/tex]?

A. 166 mm Hg
B. 0.532 L
C. Unknown



Answer :

GinnyAnswer
Let's start by assigning the given values to their respective variables.

We know:
- The initial pressure [tex]\( P_1 = 151 \)[/tex] mm Hg.
- The final pressure [tex]\( P_2 = 166 \)[/tex] mm Hg.
- The final volume [tex]\( V_2 = 0.532 \)[/tex] L.

We are asked to find the initial volume [tex]\( V_1 \)[/tex].

To determine [tex]\( V_1 \)[/tex], we would typically use the relationship provided by Boyle's Law for gases, which states that for a fixed amount of gas at constant temperature, the pressure and volume are inversely proportional:

[tex]\[ P_1 \times V_1 = P_2 \times V_2 \][/tex]

However, since [tex]\( V_1 \)[/tex] is not provided:

Let's check the options given for [tex]\( V_1 \)[/tex]:
A. 166 mm Hg
B. 0.532 L
C. unknown

Given the information at hand, the correct choice for [tex]\( V_1 \)[/tex] is:

C. unknown

So, the initial volume [tex]\( V_1 \)[/tex] is unknown.

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