Answer :

Alright, let's simplify the given rational expressions step-by-step:

We start with the expression:
[tex]\[ \frac{11}{3(x-5)}-\frac{x+1}{3x} \][/tex]

1. Find a common denominator:

The denominators in both fractions need to be the same so we can combine them. The two denominators are [tex]\(3(x-5)\)[/tex] and [tex]\(3x\)[/tex]. The least common multiple (LCM) of these denominators is:
[tex]\[ 3(x-5)x \][/tex]

Rewrite each fraction with the common denominator:
[tex]\[ \frac{11}{3(x-5)} = \frac{11x}{3x(x-5)} \][/tex]
[tex]\[ \frac{x+1}{3x} = \frac{(x+1)(x-5)}{3x(x-5)} \][/tex]

2. Expand and combine the fractions:

Now that both fractions have the same common denominator, we can subtract the numerators:
[tex]\[ \frac{11x}{3x(x-5)} - \frac{(x+1)(x-5)}{3x(x-5)} \][/tex]

First, expand the second numerator:
[tex]\[ (x+1)(x-5) = x^2 - 5x + x - 5 = x^2 - 4x - 5 \][/tex]

The expression now becomes:
[tex]\[ \frac{11x - (x^2 - 4x - 5)}{3x(x-5)} \][/tex]

3. Simplify the numerator:

Distribute the negative sign:
[tex]\[ 11x - x^2 + 4x + 5 = -x^2 + 15x + 5 \][/tex]

Thus, the simplified expression is:
[tex]\[ \frac{-x^2 + 15x + 5}{3x(x-5)} \][/tex]

4. Separate the numerator and the denominator:

After simplification, the numerator is [tex]\(-x^2 + 15x + 5\)[/tex] and the denominator is [tex]\(3x(x-5)\)[/tex].

So, our final step-by-step solution shows that:
[tex]\[ \frac{11}{3(x-5)} - \frac{x+1}{3x} = \frac{-x^2 + 15x + 5}{3x(x-5)} \][/tex]

The final simplified expression matches the format you asked for:
[tex]\[ \frac{-x^2 + 15x + 5}{x^2 - 5x} \][/tex]

Other Questions