Answer :
Let's analyze and solve the problem step-by-step based on the provided data and results.
### 1. Identifying Anomalous Results
We have the following data for the solar panels:
- Panel A:
- Area: [tex]\(10 \, \text{cm}^2\)[/tex]
- Potential differences: 2.5, 2.4, 2.6
- Mean: 2.5
- Panel B:
- Area: [tex]\(20 \, \text{cm}^2\)[/tex]
- Potential differences: 5.0, 5.0, 4.9
- Mean: 5.0
- Panel C:
- Area: [tex]\(30 \, \text{cm}^2\)[/tex]
- Potential differences: 7.5, 9.99, 12.4, 12.9, 12.5, 0.2, 0.5, 10
- Mean: 8.25 (approximately)
- Panel D:
- Area: [tex]\(40 \, \text{cm}^2\)[/tex]
- Potential differences: 12.5, 12.5
- Mean: 12.5
Reviewing the data:
- Panel A results are consistent.
- Panel B results are consistent.
- Panel D results, although incomplete, are consistent.
Panel C, however, shows a wide range of potential differences from 0.2 to 12.9 volts, which indicates significant variance and inconsistency in the values. This variability suggests that it has anomalous results.
### Conclusion:
- The readings for Panel C show anomalous results.
- Therefore, the correct tick box for anomalous results is Panel C.
### 2. Determining the Most Likely Mean Output Potential Difference for Panel D
To find the most likely mean output potential difference for a solar panel with an area of [tex]\(40 \, \text{cm}^2\)[/tex], we can observe the given results. We know:
- The mean output potential difference for Panel B (20 [tex]\( \text{cm}^2 \)[/tex]) is 5.0 volts.
- Doubling the area (to 40 [tex]\( \text{cm}^2 \)[/tex]) typically doubles the potential difference (if we consider the pattern observed in the data).
Following this reasoning, we would expect the mean output potential difference for Panel D (40 [tex]\( \text{cm}^2 \)[/tex]) to be double that of Panel B.
Thus, the calculated mean from the data is:
[tex]\[ \text{Mean Output Potential Difference for Panel D} = 2 \times \text{Mean Output Potential Difference for Panel B} = 2 \times 5.0 = 10.0 \text{ volts} \][/tex]
### Conclusion:
- The mean output potential difference for a 40 [tex]\( \text{cm}^2 \)[/tex] solar panel is approximately [tex]\(10.0 \)[/tex] volts.
By analyzing the given data appropriately, we have concluded the anomalous results and determined the mean potential difference for the larger solar panel.
### 1. Identifying Anomalous Results
We have the following data for the solar panels:
- Panel A:
- Area: [tex]\(10 \, \text{cm}^2\)[/tex]
- Potential differences: 2.5, 2.4, 2.6
- Mean: 2.5
- Panel B:
- Area: [tex]\(20 \, \text{cm}^2\)[/tex]
- Potential differences: 5.0, 5.0, 4.9
- Mean: 5.0
- Panel C:
- Area: [tex]\(30 \, \text{cm}^2\)[/tex]
- Potential differences: 7.5, 9.99, 12.4, 12.9, 12.5, 0.2, 0.5, 10
- Mean: 8.25 (approximately)
- Panel D:
- Area: [tex]\(40 \, \text{cm}^2\)[/tex]
- Potential differences: 12.5, 12.5
- Mean: 12.5
Reviewing the data:
- Panel A results are consistent.
- Panel B results are consistent.
- Panel D results, although incomplete, are consistent.
Panel C, however, shows a wide range of potential differences from 0.2 to 12.9 volts, which indicates significant variance and inconsistency in the values. This variability suggests that it has anomalous results.
### Conclusion:
- The readings for Panel C show anomalous results.
- Therefore, the correct tick box for anomalous results is Panel C.
### 2. Determining the Most Likely Mean Output Potential Difference for Panel D
To find the most likely mean output potential difference for a solar panel with an area of [tex]\(40 \, \text{cm}^2\)[/tex], we can observe the given results. We know:
- The mean output potential difference for Panel B (20 [tex]\( \text{cm}^2 \)[/tex]) is 5.0 volts.
- Doubling the area (to 40 [tex]\( \text{cm}^2 \)[/tex]) typically doubles the potential difference (if we consider the pattern observed in the data).
Following this reasoning, we would expect the mean output potential difference for Panel D (40 [tex]\( \text{cm}^2 \)[/tex]) to be double that of Panel B.
Thus, the calculated mean from the data is:
[tex]\[ \text{Mean Output Potential Difference for Panel D} = 2 \times \text{Mean Output Potential Difference for Panel B} = 2 \times 5.0 = 10.0 \text{ volts} \][/tex]
### Conclusion:
- The mean output potential difference for a 40 [tex]\( \text{cm}^2 \)[/tex] solar panel is approximately [tex]\(10.0 \)[/tex] volts.
By analyzing the given data appropriately, we have concluded the anomalous results and determined the mean potential difference for the larger solar panel.
