Answer :
To find the potential energy of a bicycle resting at the top of a hill, we need to use the formula for gravitational potential energy, which is given by:
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( g \)[/tex] is the acceleration due to gravity, and
- [tex]\( h \)[/tex] is the height.
Let's plug in the values provided:
- The mass [tex]\( m \)[/tex] of the bicycle is [tex]\( 25 \)[/tex] kg.
- The acceleration due to gravity [tex]\( g \)[/tex] is [tex]\( 9.8 \)[/tex] m/s² (standard value on Earth).
- The height [tex]\( h \)[/tex] of the hill is [tex]\( 3 \)[/tex] m.
So, the potential energy can be calculated as follows:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
When performing the multiplication, we get:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
[tex]\[ PE = 735 \, \text{J} \][/tex]
Therefore, the potential energy of the bicycle is [tex]\( 735 \)[/tex] Joules.
The correct answer is:
[tex]\[ \boxed{735 J} \][/tex]
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( g \)[/tex] is the acceleration due to gravity, and
- [tex]\( h \)[/tex] is the height.
Let's plug in the values provided:
- The mass [tex]\( m \)[/tex] of the bicycle is [tex]\( 25 \)[/tex] kg.
- The acceleration due to gravity [tex]\( g \)[/tex] is [tex]\( 9.8 \)[/tex] m/s² (standard value on Earth).
- The height [tex]\( h \)[/tex] of the hill is [tex]\( 3 \)[/tex] m.
So, the potential energy can be calculated as follows:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
When performing the multiplication, we get:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
[tex]\[ PE = 735 \, \text{J} \][/tex]
Therefore, the potential energy of the bicycle is [tex]\( 735 \)[/tex] Joules.
The correct answer is:
[tex]\[ \boxed{735 J} \][/tex]
