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Convert [tex]\( y = 6x^2 + 36x + 48 \)[/tex] to vertex form by completing the square. Choose the correct equation.

A. [tex]\( y = 6(x + 3)^2 + 156 \)[/tex]

B. [tex]\( y = 6(x + 3)^2 - 6 \)[/tex]

C. [tex]\( y = 6(x + 3)^2 + 111 \)[/tex]

D. [tex]\( y = 6(x + 3)^2 + 93 \)[/tex]



Answer :

To convert [tex]\( y = 6x^2 + 36x + 48 \)[/tex] into vertex form, we need to complete the square. Here's a detailed step-by-step solution:

1. Factor out the coefficient of [tex]\( x^2 \)[/tex] from the first two terms:
[tex]\[ y = 6(x^2 + 6x) + 48 \][/tex]

2. Complete the square inside the parentheses:
- Take half of the coefficient of [tex]\( x \)[/tex] (which is 6), square it, and add and subtract it inside the parentheses.
[tex]\[ \left(\frac{6}{2}\right)^2 = 9 \][/tex]
- Add and subtract 9 inside the parentheses:
[tex]\[ y = 6(x^2 + 6x + 9 - 9) + 48 \][/tex]
- Rewrite the expression inside the parentheses by completing the square:
[tex]\[ y = 6((x + 3)^2 - 9) + 48 \][/tex]

3. Simplify the equation by distributing the 6 and combining like terms:
- Distribute the 6:
[tex]\[ y = 6(x + 3)^2 - 6 \times 9 + 48 \][/tex]
- Simplify the constant term:
[tex]\[ y = 6(x + 3)^2 - 54 + 48 \][/tex]
- Combine like terms:
[tex]\[ y = 6(x + 3)^2 - 6 \][/tex]

Therefore, the equation in vertex form is:
[tex]\[ y = 6(x + 3)^2 - 6 \][/tex]

So, the correct answer is:
[tex]\[ \boxed{b} \][/tex]

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