A dilation has center [tex][tex]$(0,0)$[/tex][/tex]. Find the image of each point for the given scale factor.

[tex]C(3,-6) ; D_{\left(\frac{5}{3}\right)}(C)[/tex]

A. [tex][tex]$\left(\frac{18}{5}, \frac{9}{5}\right)$[/tex][/tex]
B. [tex][tex]$(-10,5)$[/tex][/tex]
C. [tex][tex]$(5,-10)$[/tex][/tex]
D. [tex][tex]$\left(\frac{9}{5}, \frac{18}{5}\right)$[/tex][/tex]



Answer :

Sure, let me walk you through the solution step-by-step to find the image of the point [tex]\( C(3, -6) \)[/tex] under the dilation with center [tex]\( (0,0) \)[/tex] and scale factor [tex]\( \frac{5}{3} \)[/tex].

1. Identify the given point and the scale factor:
The given point is [tex]\( C(3, -6) \)[/tex], and the scale factor is [tex]\( \frac{5}{3} \)[/tex].

2. Apply the scale factor to the coordinates:
To find the image of the point after the dilation, multiply both the x-coordinate and the y-coordinate of the point [tex]\( C \)[/tex] by the scale factor.

- For the x-coordinate:
[tex]\[ \text{image}_x = 3 \times \frac{5}{3} \][/tex]
Let's simplify this:
[tex]\[ \text{image}_x = 3 \times \frac{5}{3} = 5 \][/tex]

- For the y-coordinate:
[tex]\[ \text{image}_y = -6 \times \frac{5}{3} \][/tex]
Let's simplify this:
[tex]\[ \text{image}_y = -6 \times \frac{5}{3} = -10 \][/tex]

3. Combine the coordinates to form the image point:
The image of the point [tex]\( C(3, -6) \)[/tex] under the dilation is [tex]\( (5, -10) \)[/tex].

4. Check the given answer choices:
Compare the result obtained to the given options:
[tex]\[ \begin{aligned} &\text{A.} \ \left(\frac{18}{5}, \frac{9}{5}\right) \\ &\text{B.} \ (-10, 5) \\ &\text{C.} \ (5, -10) \\ &\text{D.} \ \left(\frac{9}{5}, \frac{18}{5}\right) \end{aligned} \][/tex]

The correct option is:
[tex]\[ \text{C.} \ (5, -10) \][/tex]

So, the image of the point [tex]\( C(3, -6) \)[/tex] under the dilation with the scale factor [tex]\( \frac{5}{3} \)[/tex] is [tex]\( (5, -10) \)[/tex].

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