Answer :
To determine the mean amount of precipitation in December for Washington state from 2005 to 2013, follow these steps:
1. List the precipitation data for each year:
5.98, 6.05, 7.59, 5.27, 3.11, 7.18, 2.95, 7.22, 2.61
2. Calculate the total precipitation by summing all the values:
[tex]\[ 5.98 + 6.05 + 7.59 + 5.27 + 3.11 + 7.18 + 2.95 + 7.22 + 2.61 = 47.96 \][/tex]
3. Count the number of years:
The number of values (or years) is 9.
4. Find the mean by dividing the total precipitation by the number of years:
[tex]\[ \frac{47.96}{9} = 5.328888888888889 \][/tex]
5. Round the mean to the nearest hundredth:
[tex]\[ 5.328888888888889 \approx 5.33 \][/tex]
Therefore, the mean amount of precipitation during this time, rounded to the nearest hundredth, is 5.33 inches.
The correct answer is:
[tex]\[ \boxed{5.33 \text{ inches}} \][/tex]
1. List the precipitation data for each year:
5.98, 6.05, 7.59, 5.27, 3.11, 7.18, 2.95, 7.22, 2.61
2. Calculate the total precipitation by summing all the values:
[tex]\[ 5.98 + 6.05 + 7.59 + 5.27 + 3.11 + 7.18 + 2.95 + 7.22 + 2.61 = 47.96 \][/tex]
3. Count the number of years:
The number of values (or years) is 9.
4. Find the mean by dividing the total precipitation by the number of years:
[tex]\[ \frac{47.96}{9} = 5.328888888888889 \][/tex]
5. Round the mean to the nearest hundredth:
[tex]\[ 5.328888888888889 \approx 5.33 \][/tex]
Therefore, the mean amount of precipitation during this time, rounded to the nearest hundredth, is 5.33 inches.
The correct answer is:
[tex]\[ \boxed{5.33 \text{ inches}} \][/tex]
