Answer :
To find [tex]\( P(4) \)[/tex] for the polynomial [tex]\( P(x) = 4x^2 + 3x - 6 \)[/tex] by direct substitution, follow these steps:
1. Start with the given polynomial [tex]\( P(x) = 4x^2 + 3x - 6 \)[/tex].
2. Substitute [tex]\( x = 4 \)[/tex] into the polynomial.
[tex]\[ P(4) = 4(4)^2 + 3(4) - 6 \][/tex]
3. Calculate [tex]\( 4(4)^2 \)[/tex]:
[tex]\[ 4(4)^2 = 4 \times 16 = 64 \][/tex]
4. Calculate [tex]\( 3(4) \)[/tex]:
[tex]\[ 3(4) = 3 \times 4 = 12 \][/tex]
5. Substitute the calculated values back into the expression:
[tex]\[ P(4) = 64 + 12 - 6 \][/tex]
6. Perform the addition and subtraction:
[tex]\[ 64 + 12 = 76 \][/tex]
[tex]\[ 76 - 6 = 70 \][/tex]
So, [tex]\( P(4) = 70 \)[/tex].
1. Start with the given polynomial [tex]\( P(x) = 4x^2 + 3x - 6 \)[/tex].
2. Substitute [tex]\( x = 4 \)[/tex] into the polynomial.
[tex]\[ P(4) = 4(4)^2 + 3(4) - 6 \][/tex]
3. Calculate [tex]\( 4(4)^2 \)[/tex]:
[tex]\[ 4(4)^2 = 4 \times 16 = 64 \][/tex]
4. Calculate [tex]\( 3(4) \)[/tex]:
[tex]\[ 3(4) = 3 \times 4 = 12 \][/tex]
5. Substitute the calculated values back into the expression:
[tex]\[ P(4) = 64 + 12 - 6 \][/tex]
6. Perform the addition and subtraction:
[tex]\[ 64 + 12 = 76 \][/tex]
[tex]\[ 76 - 6 = 70 \][/tex]
So, [tex]\( P(4) = 70 \)[/tex].
