Is the equation [tex]\( 5h + 2h^2 = 7h \)[/tex] a true statement?

Substitute a value other than 0 or 1 for [tex]\( h \)[/tex], and evaluate [tex]\( 5h + 2h^2 \)[/tex] and [tex]\( 7h \)[/tex] to support your answer.



Answer :

Let's start by selecting a value for [tex]\( h \)[/tex] that is neither 0 nor 1. For this demonstration, let's choose [tex]\( h = 3 \)[/tex].

1. First, we need to evaluate the left-hand side expression [tex]\( 5h + 2h^2 \)[/tex]:
[tex]\[ 5h + 2h^2 \][/tex]

2. Substitute [tex]\( h = 3 \)[/tex] into the expression:
[tex]\[ 5(3) + 2(3)^2 \][/tex]

3. Calculate [tex]\( 5(3) \)[/tex]:
[tex]\[ 5 \times 3 = 15 \][/tex]

4. Next, calculate [tex]\( 2(3)^2 \)[/tex]:
[tex]\[ 2 \times 3^2 = 2 \times 9 = 18 \][/tex]

5. Add the results from steps 3 and 4:
[tex]\[ 15 + 18 = 33 \][/tex]

So, the left-hand side [tex]\( 5h + 2h^2 \)[/tex] evaluates to 33 when [tex]\( h = 3 \)[/tex].

Next, let's evaluate the right-hand side expression [tex]\( 7h \)[/tex]:

1. Using the same value [tex]\( h = 3 \)[/tex]:
[tex]\[ 7h \][/tex]

2. Substitute [tex]\( h = 3 \)[/tex] into the expression:
[tex]\[ 7(3) \][/tex]

3. Calculate [tex]\( 7(3) \)[/tex]:
[tex]\[ 7 \times 3 = 21 \][/tex]

So, the right-hand side [tex]\( 7h \)[/tex] evaluates to 21 when [tex]\( h = 3 \)[/tex].

Now, compare the two results:

- Left-hand side: [tex]\( 33 \)[/tex]
- Right-hand side: [tex]\( 21 \)[/tex]

Since [tex]\( 33 \)[/tex] is not equal to [tex]\( 21 \)[/tex], the statement [tex]\( 5h + 2h^2 = 7h \)[/tex] is not true when [tex]\( h = 3 \)[/tex].

Hence, we can conclude that [tex]\( 5h + 2h^2 = 7h \)[/tex] is not a true statement for [tex]\( h = 3 \)[/tex], as the left-hand side (33) does not equal the right-hand side (21).

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