Answer :
To determine the velocity of the deer, we start with the relationship between momentum, mass, and velocity. The formula for momentum ([tex]\(p\)[/tex]) is given by:
[tex]\[ p = m \times v \][/tex]
where:
- [tex]\( p \)[/tex] is the momentum,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( v \)[/tex] is the velocity.
In this case, we are given:
- The mass of the deer ([tex]\( m \)[/tex]) is [tex]\( 68 \)[/tex] kg,
- The momentum of the deer ([tex]\( p \)[/tex]) is [tex]\( 952 \)[/tex] kg·m/s.
We need to solve for the velocity ([tex]\( v \)[/tex]). To do this, we can rearrange the momentum formula to solve for [tex]\( v \)[/tex]:
[tex]\[ v = \frac{p}{m} \][/tex]
Substitute the given values into the equation:
[tex]\[ v = \frac{952 \, \text{kg} \cdot \text{m/s}}{68 \, \text{kg}} \][/tex]
Now, perform the division:
[tex]\[ v = 14 \, \text{m/s} \][/tex]
Thus, the velocity of the deer is [tex]\( 14 \)[/tex] meters per second.
[tex]\[ p = m \times v \][/tex]
where:
- [tex]\( p \)[/tex] is the momentum,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( v \)[/tex] is the velocity.
In this case, we are given:
- The mass of the deer ([tex]\( m \)[/tex]) is [tex]\( 68 \)[/tex] kg,
- The momentum of the deer ([tex]\( p \)[/tex]) is [tex]\( 952 \)[/tex] kg·m/s.
We need to solve for the velocity ([tex]\( v \)[/tex]). To do this, we can rearrange the momentum formula to solve for [tex]\( v \)[/tex]:
[tex]\[ v = \frac{p}{m} \][/tex]
Substitute the given values into the equation:
[tex]\[ v = \frac{952 \, \text{kg} \cdot \text{m/s}}{68 \, \text{kg}} \][/tex]
Now, perform the division:
[tex]\[ v = 14 \, \text{m/s} \][/tex]
Thus, the velocity of the deer is [tex]\( 14 \)[/tex] meters per second.
