Which equation is the inverse of [tex]y=2x^2-8[/tex]?

A. [tex]y= \pm \sqrt{\frac{x+8}{2}}[/tex]
B. [tex]y=\frac{ \pm \sqrt{x+8}}{2}[/tex]
C. [tex]y= \pm \sqrt{\frac{x}{2}+8}[/tex]
D. [tex]y=\frac{ \pm \sqrt{x}}{2}+4[/tex]



Answer :

To find the inverse of the function \( y = 2x^2 - 8 \), we need to follow a sequence of steps to express \( x \) in terms of \( y \) and then solve for \( y \). Here is a detailed, step-by-step solution:

1. Start with the given equation:
[tex]\[ y = 2x^2 - 8 \][/tex]

2. Isolate \( x^2 \):
Add 8 to both sides to get:
[tex]\[ y + 8 = 2x^2 \][/tex]

3. Solve for \( x^2 \):
Divide both sides by 2:
[tex]\[ \frac{y + 8}{2} = x^2 \][/tex]

4. Solve for \( x \):
Take the square root of both sides. Remember that taking the square root introduces both the positive and negative solutions:
[tex]\[ x = \pm \sqrt{\frac{y + 8}{2}} \][/tex]

5. Express the inverse function:
To express the inverse function \( y \) in terms of \( x \), we interchange \( x \) and \( y \):
[tex]\[ y = \pm \sqrt{\frac{x + 8}{2}} \][/tex]

So, the equation of the inverse function is:
[tex]\[ y = \pm \sqrt{\frac{x + 8}{2}} \][/tex]

Hence, the correct inverse equation that matches the given choices is:
[tex]\[ y = \pm \sqrt{\frac{x + 8}{2}} \][/tex]

Other Questions