The density (mass/volume) of aluminum is [tex]2.70 \times 10^3 \, \text{kg/m}^3[/tex].

What is the mass of an aluminum cylinder that has a volume of [tex]1.50 \, \text{m}^3[/tex]?

A. [tex]5.56 \times 10^{-4} \, \text{kg}[/tex]

B. [tex]1.50 \times 10^{-3} \, \text{kg}[/tex]

C. [tex]1.80 \times 10^3 \, \text{kg}[/tex]

D. [tex]4.05 \times 10^3 \, \text{kg}[/tex]



Answer :

To solve the problem of finding the mass of an aluminum cylinder given its density and volume, we can use the formula for mass:

[tex]\[ \text{mass} = \text{density} \times \text{volume} \][/tex]

### Given Data

- Density of aluminum, \(\rho = 2.70 \times 10^3 \, \text{kg/m}^3\)
- Volume of the aluminum cylinder, \(V = 1.50 \, \text{m}^3\)

### Step-by-Step Solution

1. Identify the formula:

The formula to calculate mass is:
[tex]\[ \text{mass} = \rho \times V \][/tex]

2. Substitute the given values into the formula:

[tex]\[ \text{mass} = (2.70 \times 10^3 \, \text{kg/m}^3) \times (1.50 \, \text{m}^3) \][/tex]

3. Simplify the multiplication:

First, calculate the product of the numerical values:
[tex]\[ 2.70 \times 1.50 = 4.05 \][/tex]

Then, account for the powers of ten:
[tex]\[ 10^3 \, \text{kg/m}^3 \times \text{m}^3 = 10^3 \, \text{kg} \][/tex]

4. Combine these results:

[tex]\[ \text{mass} = 4.05 \times 10^3 \, \text{kg} \][/tex]

Alternatively, this can be written in standard notation as:
[tex]\[ \text{mass} = 4050 \, \text{kg} \][/tex]

### Conclusion
The mass of the aluminum cylinder is found to be \(4050 \, \text{kg}\).

Thus, the correct option from the given choices is:
[tex]\[ \boxed{4.05 \times 10^3 \, \text{kg}} \][/tex]

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