Answer :
Answer:
(the magnitude of the force) × (the perpendicular distance of the line of action of the force from the point.)
Explanation:
The moment of a force depends on the magnitude of the force and the distance from the axis of rotation. The moment of a force about a point is (the magnitude of the force) × (the perpendicular distance of the line of action of the force from the point).
Answer:
Explanation:
The moment of a force, also known as torque, is calculated using the formula:The moment of a force, also known as torque, is calculated using the formula:
\[ Torque = Force \times Distance \times sin(\theta) \]
where:
- Specifically, force is equal to the magnitude of the applied force.
- DISTANCE is the perpendicular of the force line of action to the point of rotation or the pivot point.
- where \(\theta\) is the angle between the force vector and the distance vector from the pivot point to the point of force application.
To break it down:
1. **Force**: This is the force that acts on an object to either pull or shove it in a certain direction.
2. **Distance**: This is the smallest perpendicular to the line along which the force acts passing through the axis of rotation. To calculate torque, it should be perpendicular to the force vector, meaning it should be at 90 degrees with the force vector.
3. **Angle \(\theta\)**: This angle simplifies an analysis when the force is not applied perpendicular to the lever arm or in other words the distance. Whereas in such situations, you utilize the part of the force that is applied perpendicular to the lever arm.
If the force and the lever arm are perpendicular, the calculation simplifies to:If the force and the lever arm are perpendicular, the calculation simplifies to:
\[ \text{Torque} = \text{Force} \ast \text{Distance} \]
Several types of torque measurement are known and the most common measurement unit is newton meter (Nm) according to the SI system.
### Example Calculation:
Illustration Suppose you have force of 10 N and which is applied perpendicularly to the lever arm or distance of 2 meters. The torque (moment of force) would be:The torque (moment of force) would be:
\[ \text{Torque} = 10 \, \text{N} \times 2 \, \text{m} = 20 \, \text{Nm} \]
If the force is not in the perpendicular to the mentioned lever arm, you will also have to consider sin0, where 0 is the angle between force vector and direction of the lever arm.
