The table shows the distribution of ages of 45 children who attended a birthday party.

\begin{tabular}{|l|l|l|l|l|l|l|l|l|}
\hline Age (yrs) & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\
\hline Frequency & 2 & 6 & 5 & 4 & 6 & 9 & 8 & 5 \\
\hline
\end{tabular}



Answer :

To find the mean (average) age of the 45 children who attended the birthday party, we need to follow these steps:

1. Identify the Age Groups and Their Frequencies:

We have the age groups: 3, 4, 5, 6, 7, 8, 9, and 10 years.
The corresponding frequencies (number of children in each age group) are: 2, 6, 5, 4, 6, 9, 8, and 5.

2. Verify the Total Number of Children:

Adding up the frequencies:
[tex]\[ 2 + 6 + 5 + 4 + 6 + 9 + 8 + 5 = 45 \][/tex]

This confirms that the total number of children is 45.

3. Calculate the Sum of Ages Multiplied by Their Frequencies:

- For age 3: \(3 \times 2 = 6\)
- For age 4: \(4 \times 6 = 24\)
- For age 5: \(5 \times 5 = 25\)
- For age 6: \(6 \times 4 = 24\)
- For age 7: \(7 \times 6 = 42\)
- For age 8: \(8 \times 9 = 72\)
- For age 9: \(9 \times 8 = 72\)
- For age 10: \(10 \times 5 = 50\)

Adding these up:
[tex]\[ 6 + 24 + 25 + 24 + 42 + 72 + 72 + 50 = 315 \][/tex]

4. Calculate the Mean (Average) Age:

The mean age is computed by dividing the total sum of ages by the total number of children:
[tex]\[ \text{Mean Age} = \frac{\text{Sum of Ages}}{\text{Total Number of Children}} = \frac{315}{45} = 7.0 \][/tex]

5. Summary:

- Total number of children: 45
- Sum of ages multiplied by their frequencies: 315
- Mean (average) age: 7.0

Therefore, the mean age of the children who attended the birthday party is 7.0 years.

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