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What is the equation of the line that is perpendicular to the given line and has an [tex]$x$[/tex]-intercept of 6?

A. [tex]$y = -\frac{3}{4} x + 8$[/tex]
B. [tex]$y = -\frac{3}{4} x + 6$[/tex]
C. [tex]$y = \frac{4}{3} x - 8$[/tex]
D. [tex]$y = \frac{4}{3} x - 6$[/tex]



Answer :

To determine the equation of the line that is perpendicular to the given line \( y = -\frac{3}{4} x + b \) and has an \( x \)-intercept of 6, follow these detailed steps:

Step 1: Identify the slope of the given line.
The given line is in the form \( y = mx + b \), where \( m \) is the slope. For the given line \( y = -\frac{3}{4} x + b \), the slope \( m \) is \( -\frac{3}{4} \).

Step 2: Determine the slope of the perpendicular line.
The slope of a line that is perpendicular to another is the negative reciprocal of the original slope. The negative reciprocal of \( -\frac{3}{4} \) is \( \frac{4}{3} \).

Step 3: Use the \( x \)-intercept to find the y-intercept.
The \( x \)-intercept of a line is the point where the line crosses the \( x \)-axis. At this point, \( y = 0 \). Given the \( x \)-intercept is 6, the line passes through the point \( (6, 0) \).

Step 4: Substitute the values into the line equation to solve for \( b \).
The general form of the equation of the line is \( y = mx + b \). Using the slope \( m = \frac{4}{3} \) and the point \( (6, 0) \), substitute these values into the equation to solve for \( b \):
[tex]\[ 0 = \left( \frac{4}{3} \right) \cdot 6 + b \][/tex]
[tex]\[ 0 = 8 + b \][/tex]
[tex]\[ b = -8 \][/tex]

Step 5: Write the equation of the line.
Now that we have the slope \( \frac{4}{3} \) and the y-intercept \( b = -8 \), the equation of the line is:
[tex]\[ y = \frac{4}{3} x - 8 \][/tex]

Identify the correct option:
From the given options, the correct equation that matches our result is:
[tex]\[ y = \frac{4}{3} x - 8 \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{3} \][/tex]

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